Chaste Tree
»Chaste Tree consists of the dried ripe fruits of Vitex agnus-castus L.(Fam.Verbenaceae).It contains not less than 0.05percent of agnuside and not less than 0.08percent of casticin,calculated on the dried basis.
Packaging and storage— Preserve in a well-closed container,and store at controlled room temperature.
Labeling— The label states the Latin binomial and,following the official name,the part of the plant contained in the article.
USP Reference standards á11ñ USP Agnuside RS.USP Casticin RS.USP Powdered Chaste Tree Extract RS.
Botanic characteristics—
Macroscopic— Mature chaste tree fruits are spherical to ovoid,2to 4mm in diameter,very hard,usually with a short pedicil.The fruit is reddish brown to black,slightly rough,and covered with glandular hairs.There are four grooves perpendicular to one another,and a slight depression on the apex,more evident on large fruits.The internal appearance of the fruit is yellowish.The internal structure of the fruit includes four compartments,each containing an oblong seed with a high fat content.Agroup of up to six spongy,light tan,immature fruits may also accompany mature fruits.The fruit is often covered by a tubular,greenish-gray,fine tomentous calyx,which is persistent and has five teeth.
Microscopic— The exocarp is brown and narrow,consisting of parenchymatous cells with thin walls and partially lignified cells with many pitted thickenings on the inside.In surface view,the exocarp shows an epidermis of polygonal cells with irregular thickenings and glandular hairs,each with a short single-celled stalk and a four-celled head containing essential oil.The outer mesocarp consists of several layers of brown,isodiametric parenchyma cells.The inner mesocarp consists of finely pitted sclerenchymatous cells,some with moderately thickened walls,others consisting of isodiametric stone cells with small lumen.The endocarp consists of a layer of small brown sclereid cells.The seeds are small,having large cotyledons surrounded by thin-walled,large parenchymatous cells that have ribbed thickenings.The nutritive tissue and the cells of the germ contain aleuron grains and oil globules.Starch is absent.The outer epidermis of calyx is composed of polygonal cells,covered by abundant unicellular or multicellular curved trichomes.The inner epidermis of calyx is glabrous and composed of rectangular,elongated cells with slightly wavy walls.
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Identification—
A: Thin-Layer Chromatographic Identification Test á201ñ
Test solution— Transfer about 1g of the powdered plant material to a screw-capped centrifuge tube.Add 10mLof methanol,and heat in a water bath at 60for 10to 15minutes,cool,and filter.Apply 60µLto the plate in bands that are 2cm in length.
Standard solution— Transfer about 100mg of USP Powdered Chaste Tree Extract RSto a screw-capped centrifuge tube.Add 1mLof methanol,and heat in a water bath at 60for 10minutes.Centrifuge,and use the clear supernatant.Apply 90µLto the plate.
Developing solvent system— Use a mixture of ethyl acetate,methanol,and water (77:15:8).
Spray reagent— Prepare a solution of p-dimethylaminobenzaldehyde in 1Nhydrochloric acid containing 10mg per mL.
Procedure— Develop the chromatogram to a length of not less than 12cm,and dry the plate in a current of air.Spray the plate withSpray reagent,and heat for 10minutes at 120.The chromatogram obtained from theTest solution shows the following:a blue zone (at an RFvalue of about 0.21)that is due to the presence of aucubin and that corresponds in color andRFvalue to a similar zone in the chromatogram of theStandard solution;a blue zone (at an RFvalue of about 0.44)as a result of the presence of agnuside that corresponds in color andRFvalue to a similar zone in the chromatogram of theStandard solution;and one broad zone,violet in the middle,that is near the solvent front and that corresponds in color andRFvalue to a similar zone in the chromatogram of theStandard solution.Other colored zones of varying intensities may be observed in the chromatogram of the Test solution.
B:USP28 The chromatogram of theTest solution in the test forContent of casticin shows a peak at the retention time corresponding to the casticin peak in the chromatogram of theStandard solution.
Microbial enumeration á2021ñ It meets the requirements of the tests for absence of Salmonellaspecies and Escherichia coli.The total aerobic microbial count does not exceed 106cfu per g,the total combined molds and yeast count does not exceed 104cfu per g,and the enterobacterial count does not exceed 103cfu.
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Loss on drying á731ñ Dry 1g at 105for 2hours.It losesUSP28not more than 10.0%.
Foreign organic matter á561ñ: not more than 3.0%.
Total ash á561ñ: not more than 8.0%.
Acid-insoluble ash á561ñ: not more than 2.0%.
Pesticide residues á561ñ: meets the requirements.
Heavy metals,Method IIIá231ñ: not more than 20µg per g.
Content of casticin—
Solution A— Use filtered and degassed methanol.
Solution B— Use a filtered and degassed solution of 5.88g of phosphoric acid in 1000mLof water.
Mobile phase— Use variable mixtures of Solution Aand Solution Bas directed for Chromatographic system.Make adjustments if necessary (see System Suitability under Chromatography á621ñ).
Standard solution— Dissolve an accurately weighed quantity of USP Casticin RSin methanol,with sonication.Dilute quantitatively,and stepwise if necessary,with methanol to obtain a solution having a known concentration of about 0.05mg per mL.Filter through a cellulose membrane having a 0.45-µm or finer porosity.
Test solution— Accurately weigh approximately 1000mg of ground plant material,and place in a suitable container with a stopper.Extract twice with 40mLof methanol,using a hand homogenizer at 19,000rpm for 2minutes.Filter each supernatant,and transfer to a 250-mLround-bottom flask.Rinse the residue with methanol,and filter the resulting solution into the flask.Evaporate the combined extract to dryness.Dissolve the residue in methanol,quantitatively transfer to a 20-mLvolumetric flask,and dilute with methanol to volume.Filter through a cellulose membrane having a 0.45-µm or finer porosity.
Chromatographic system(see Chromatography á621ñ)— The liquid chromatograph is equipped with a 348-nm detector and a 3.1-mm ×12.5-cm column that contains 5-µm packing L1.The column temperature is maintained at 25.The flow rate is about 1.0mLper minute.The chromatograph is programmed as follows.
Time
(minutes)
Solution A
(%)
Solution B
(%)
Elution
0 50 50 equilibration
0–13 50®65 50®35 linear gradient
13–18 65®100 35®0 linear gradient
18–23 100®50 0®50 linear gradient
Chromatograph the Standard solution,and record the peak responses as directed for Procedure:the tailing factor for casticin is not more than 2.0;and the relative standard deviation for replicate injections is not more than 2.0%.
Procedure— Separately inject equal volumes (about 10µL)of theStandard solutionand the Test solutioninto the chromatograph,record the chromatograms,and measure the areas of the analyte peaks.Identify the retention time of the peak corresponding to casticin in the Test solutionby comparison with the chromatogram of the Standard solution.Calculate the percentage of casticin in the portion of Chaste Tree taken by the formula:
2000(C/W)(rU/rS),
in which Cis the concentration,in mg per mL,of USP Casticin RSin the Standard solution;Wis the weight,in mg,of the Chaste Tree taken to prepare the Test solution;and rUand rSare the peak responses of casticin obtained from the Test solutionand the Standard solution,respectively.
Content of agnuside—
Solvent: a mixture of water and methanol (95:5).
Solution A— Use filtered and degassed acetonitrile.
Solution B— Use a filtered and degassed solution of 5.88g of phosphoric acid in 1000mLof water.
Standard solution— Dissolve an accurately weighed quantity of USP Agnuside RSin Solvent,with sonication.Dilute quantitatively,and stepwise if necessary,with methanol to obtain a solution having a known concentration of about 0.125mg per mL.Filter through a cellulose membrane having a 0.45-µm or finer porosity.
Test solution— Accurately weigh approximately 1000mg of ground plant material,and place in a suitable container with a stopper.Extract twice with 40mLof methanol,using a hand homogenizer at 19,000rpm for 2minutes.Centrifuge,and transfer each supernatant to a 250-mLround-bottom flask.Rinse the residue with methanol,and filter the resulting solution into the flask.Evaporate the combined extract to dryness,and dissolve the residue in 2mLof Solvent.Quantitatively transfer the solution to a solid-phase extraction cartridge packed with neutral aluminum oxide previously conditioned with 5mLof Solvent.Connect the cartridge to a vacuum pressure not exceeding 300mbar,and collect the eluate.Rinse the round-bottom flask with 2mLof Solvent,and pass this solution through the cartridge,apply the vacuum,and collect the eluate.Rinse the cartridge with 4mLof Solvent,and collect the eluate.Combine the eluates from the cartridge,transfer to a 10-mLvolumetric flask,and dilute with Solventto volume.
Chromatographic system (see Chromatography á621ñ)— The liquid chromatograph is equipped with a 258-nm detector and a 3.1-mm ×12.5-cm column that contains 5-µm packing L1.The column temperature is maintained at 25.The flow rate is about 1.3mLper minute.The chromatograph is programmed as follows.
Time
(minutes)
Solution A
(%)
Solution B
(%)
Elution
0 7 93 equilibration
0–0.6 7®10 93®90 linear gradient
0.6–5 10 90 isocratic
5–7 10®14 90®86 linear gradient
7–13 14®15 86®85 linear gradient
13–13.1 15®100 85®0 linear gradient
13.1–18 100 0 isocratic
18–18.1 100®7 0®93 linear gradient
18.1–23 7 93 re-equilibration
Chromatograph the Standard solution,and record the peak responses as directed for Procedure:the tailing factor for agnuside is not more than 2.0;and the relative standard deviation for replicate injections is not more than 2.0%.
Procedure— Separately inject equal volumes (about 10µL)of the Standard solutionand the Test solutioninto the chromatograph,record the chromatograms,and measure the areas for the analyte peaks.Identify the retention time of the peak corresponding to agnuside in the the Test solutionby comparison with the chromatogram obtained from the Standard solution.Calculate the percentage of agnuside in the portion of Chaste Tree taken by the formula:
1000(C/W)(rU/rS),
in which Cis the concentration,in mg per mL,of USP Agnuside RSin the Standard solution;Wis the weight,in mg,of the Chaste Tree taken to prepare the Test solution;and rUand rSare the peak responses of agnuside obtained from the Test solutionand the Standard solution,respectively.
Auxiliary Information— Staff Liaison:Gabriel I.Giancaspro,Ph.D.,Senior Scientist and Latin American Specialist
Expert Committee:(DSB)Dietary Supplements:Botanicals
USP28–NF23Page 2064
Pharmacopeial Forum:Volume No.30(2)Page 546
Phone Number:1-301-816-8343