Packaging and storage
Preserve in well-closed containers.
Labeling
The label states the content of anhydrous aluminum zirconium trichlorohydrate.
Identification
Asolution (1in 10)responds to the test for
Chloride á191ñ.
pHá791ñ:
between 3.0and 5.0,in a solution [15in 100(w/w)].
Heavy metals,Method Iá231ñ
Proceed as directed in the chapter,except to use the following modifications.
Test Preparation
Prepare as directed in the chapter.If the solution is not clear after dilution to 40mL,heat for several minutes between 60

and 80

,and cool to room temperature.If the solution remains cloudy,repeat from the beginning with the following modification:add 3mLof hydrochloric acid prior to adjustment of the pHwith 6Nammonium hydroxide.
Monitor Preparation
Prepare as directed in the chapter,using the same modifications described for Test Preparationif necessary.
Procedure
To each of the three tubes containing the
Standard Preparation,the
Test Preparation,and the
Monitor Preparation,add 2mLof
pH3.5Acetate Buffer,and heat gently to between 60

and 80

.To the
Standard Preparationadd 6drops of sodium sulfide TS.To the
Test Preparationand the
Monitor Preparationadd 12drops of sodium sulfide TS.Cool to room temperature,and dilute the contents of each tube with water to 50mL.Gently mix each tube by inverting twice.Allow to stand for 5minutes,and view downward over a white surface.The color of the solution from the
Test Preparationis not darker than that of the solution from the
Standard Preparation,and the color of the solution from the
Monitor Preparationis the same as or darker than the color of the solution from the
Standard Preparation.If the color of the solution from the
Monitor Preparationis lighter than the color of the solution from the
Standard Preparation,repeat the procedure with the following modification:after the heating step,to the
Monitor Preparationand the
Test Preparationadd 1.0mL,instead of 12drops,of sodium sulfide TS.Not more than 20µg per g is found.
Limit of iron
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate,proceed as directed in the test for
Limit of ironunder
Aluminum Zirconium Octachlorohydrate.The specified result is obtained (150µg per g limit).
Content of aluminum
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate,proceed as directed in the test for
Content of aluminumunder
Aluminum Zirconium Octachlorohydrate.Use the result obtained to calculate the
Aluminum/
zirconium atomic ratioand the (
Aluminum plus zirconium)/
chloride atomic ratio.
Content of zirconium
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate,proceed as directed in the test for
Content of zirconiumunder
Aluminum Zirconium Octachlorohydrate.Use the result obtained to calculate the
Aluminum/
zirconium atomic ratioand the (
Aluminum plus zirconium)/
chloride atomic ratio.
Aluminum/zirconium atomic ratio
Divide the percentage of aluminum found in the test for Content of aluminumby the percentage of zirconium found in the test for Content of zirconium,and multiply by 92.97/26.98,in which 92.97is the atomic weight of zirconium corrected for 2%hafnium content,and 26.98is the atomic weight of aluminum:the ratio is between 2.0:1and 5.99:1.
Content of chloride
Using Aluminum Zirconium Trichlorohydrate instead of Aluminum Zirconium Octachlorohydrate,proceed as directed in the test for
Content of chlorideunder
Aluminum Zirconium Octachlorohydrate.Use the result obtained to calculate the (
Aluminum plus zirconium)/
chloride atomic ratio.
(Aluminum plus zirconium)/chloride atomic ratio
Calculate the (aluminum plus zirconium)/chloride atomic ratio by the formula:
[(Al/26.98)+(Zr/92.97)]/(Cl/35.453),
in which
Al,
Zr,and
Clare the percentages of aluminum,zirconium,and chloride as determined in the tests for
Content of aluminum,
Content of zirconium,and
Content of chloride,respectively;26.98is the atomic weight of aluminum;92.97is the atomic weight of zirconium corrected for 2%hafnium content;and 35.453is the atomic weight of chlorine:the ratio is between 2.1:1and 1.51:1.
Assay
Calculate the percentage of anhydrous aluminum zirconium trichlorohydrate in the Aluminum Zirconium Trichlorohydrate Gly by the formula:
Al({26.98y+92.97+17.01[3y+4-(y+1)/z]+35.453(y+1)/z}/26.98y),
in which
Alis the percentage of aluminum found in the test for
Content of aluminum,
yis the aluminum/zirconium atomic ratio found in the test for
Aluminum/
zirconium atomic ratio,
zis the (aluminum plus zirconium)/chloride atomic ratio found in the test for (
Aluminum plus zirconium)/
chloride atomic ratio,26.98is the atomic weight of aluminum,92.97is the atomic weight of zirconium corrected for 2%hafnium content,17.01is the molecular weight of the hydroxide anion (OH),and 35.453is the atomic weight of chlorine (Cl).