Chromatographic purity
Phosphate buffer
Transfer 6.8mLof phosphoric acid to a 2000-mLvolumetric flask,add about 1900mLof water,and mix.Adjust with sodium hydroxide solution (1in 2)to a pHof 3.0,dilute with water to volume,and mix.
Mobile phase
Prepare a filtered and degassed mixture of acetonitrile,
Phosphate buffer,and methanol (56:40:4).Make adjustments if necessary (see
System Suitabilityunder
Chromatography á621ñ).
Test solution
Transfer about 20mg of Apraclonidine Hydrochloride,accurately weighed,to a 25-mLvolumetric flask,dissolve in and dilute with Mobile phaseto volume,and mix.
Chromatographic system
(see
Chromatography á621ñ)The liquid chromatograph is equipped with a 220-nm detector and an 8-mm ×100-mm column that contains packing L7.The flow rate is about 3mLper minute.Chromatograph the
System suitability solution,and record the peak responses as directed for
Procedure:the tailing factor for the apraclonidine peak is not more than 2.2,and the relative standard deviation for replicate injections is not more than 2.0%.
Procedure
Inject about 20µLof the
Test solutioninto the chromatograph,record the chromatogram,and measure the areas for the major peaks.
[NOTEAllow about five times the elution time of apraclonidine before making the next injection.
]Calculate the percentage of each peak,other than the solvent peak and the apraclonidine peak,in the specimen of Apraclonidine Hydrochloride taken by the same formula:
100ri/rt,
in which
riis the response of each peak other than the principal peak,and
rtis the sum of the responses of all of the peaks,excluding that of the solvent peak:not more than 1.0%for any individual impurity and not more than 2.0%total impurities are found.
Assay
Dissolve about 125mg of Apraclonidine Hydrochloride,accurately weighed,in 40mLof glacial acetic acid.Add 10mLof mercuric acetate TS,and titrate with 0.1Nperchloric acid VS,determining the endpoint potentiometrically from the second inflection point,using a calomel-glass electrode system (see
Titrimetry á541ñ).Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 14.08mg of C
9H
10Cl
2N
4·HCl.