Chromatographic purity
Dissolve a quantity of Norfloxacin in a mixture of methanol and methylene chloride (1:1)to obtain a test solution containing 8.0mg per mL.Dissolve 4.0mg of
USP Norfloxacin RSin 1mLof glacial acetic acid,add 4mLof methanol,and mix.To 1mLof this Standard stock solution add 9mLof the mixture of methanol and methylene chloride (1:1)to obtain
Comparison solution A.Dilute a portion of this solution with an equal volume of the mixture of methanol and methylene chloride (1:1)to obtain
Comparison solution B.Separately apply 5µLof the test solution,1,1.5,and 2µLof
Comparison solution A,and 5µLof
Comparison solution Bto a suitable high-performance thin-layer chromatographic plate (see
Chromatography á621ñ)coated with a 0.25-mm layer of silica gel mixture,previously washed with methanol and air-dried.The spots of
Comparison solutions Aand
Bare equivalent to 0.2,0.3,0.4,and 0.5%of impurities,respectively.Place the plate in a paper-lined chromatographic chamber previously equilibrated with a solvent system consisting of a mixture of chloroform,methanol,toluene,diethylamine,and water (40:40:20:14:8).Seal the chamber and allow the chromatogram to develop until the solvent front has moved about nine-tenths of the length of the plate.Remove the plate from the chamber,mark the solvent front,allow the solvent to evaporate,and examine the plate under both short-and long-wavelength UVlight.Compare the intensities of any secondary spots observed in the chromatogram of the test solution with those of the principal spots in the chromatograms of
Comparison solutions Aand
B:the sum of the intensities of secondary spots obtained from the test solution corresponds to not more than 0.5%of impurities.
Assay
Dissolve about 460mg of Norfloxacin,accurately weighed,in 100mLof glacial acetic acid.Titrate potentiometrically with 0.1Nperchloric acid VSusing a suitable anhydrous electrode system (see
Titrimetry á541ñ).
[NOTERemove any aqueous solution in the electrode(s),render anhydrous,and fill with 0.1Nlithium perchlorate in acetic anhydride.
]Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 31.93mg of C
16H
18FN
3O
3.