Packaging and storage
Preserve in well-closed containers.
Identification,
Infrared Absorption á197Kñ.
Specific rotation á781Sñ:
between +26.3

and +27.7

.
Test solution:
80mg per mL,in 6Nhydrochloric acid.
Chloride á221ñ
A1.0-g portion shows no more chloride than corresponds to 0.70mLof 0.020Nhydrochloric acid (0.05%).
Sulfate á221ñ
A1.0-g portion shows no more sulfate than corresponds to 0.30mLof 0.020Nsulfuric acid (0.03%).
Chromatographic purity
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Dissolve an accurately weighed quantity of Arginine in 2Nhydrochloric acid to obtain a solution having a concentration of 10mg per mL.Apply 5µL.
Standard solution
Dissolve an accurately weighed quantity of USPL-Arginine RSin 0.1Nhydrochloric acid to obtain a solution having a known concentration of about 0.05mg per mL.Apply 5µL.[NOTEThis solution has a concentration equivalent to about 0.5%of that of the Test solution.]
Spray reagent
Dissolve 0.2g of ninhydrin in 100mLof a mixture of butyl alcohol and 2Nacetic acid (95:5).
Developing solvent system
Prepare a mixture of isopropyl alcohol and ammonium hydroxide (70:30).
Procedure
Proceed as directed for
Thin-Layer Chromatographyunder
Chromatography á621ñ.Dry the plate between 100

and 105

until the ammonia disappears completely.Spray with
Spray reagent,and heat between 100

and 105

for about 15minutes.Examine the plate under white light.The chromatogram obtained from the
System suitability solutionexhibits two clearly separated spots.Any secondary spot in the chromatogram obtained from the
Test solutionis not larger or more intense than the principal spot in the chromatogram obtained from the
Standard solution:not more than 0.5%of any individual impurity is found;and not more than 2.0%of total impurities is found.
Organic volatile impurities,Method Iá467ñ:
meets the requirements.
Solvent
Use water.
Assay
Transfer about 80mg of Arginine,accurately weighed,to a 125-mLflask,dissolve in a mixture of 3mLof formic acid and 50mLof glacial acetic acid,and titrate with 0.1Nperchloric acid VS,determining the endpoint potentiometrically.Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 8.710mg of C6H14N4O2.