Packaging and storage
Store at 25

,excursion permitted between 15

and 30

.Preserve in a well-closed container,and protect from moisture and excessive heat.
Botanical characteristics
Macroscopic
Bark pieces are typically 1to 3cm thick.The inner bark is plane to slightly concave,whitish to light brown,striped longitudinally;shiny and of slightly irregular surface,only a few millimeters thick.Abrupt change to a sequence of hard,convex,nearly parallel layers alternating with smooth,light brown layers.Up to 50or more layers present,depending on the age of the bark.Outer surface of bark is dark reddish brown composed of irregular scaly patches,with deep V-shaped fissures.Outer surface may also be gray,gray-green,or green-yellow due to presence of lichens.
Microscopic (transverse section of bark)
Light inner bark has irregular lateral stripes consisting of three to five cell layers of long,slender sieve cells with large pitted horizontal cell walls and large polygonal parenchyma cells containing single,irregular,rounded starch grain,3to 15mm wide.Lateral stripes are separated from each other by ray parenchyma cells.Ray parenchyma cells are homogeneous in appearance,one to four cell layers thick and four and twenty cell layers high,each cell containing single,irregular,rounded starch grain,3to 15mm wide.Cylindrical parenchyma cells with thin cell wall arranged in vertical rows with calcium oxalate prisms are also present.Outer part of the inner bark contains plate-shaped cells of undifferentiated periderm and older periderm with multiple layers of phellogen.The phellogen grows three to seven rows of phellum to the exterior and two to four rows of small cell phelloderm to the interior.The oldest and outermost part of the bark is composed of lignified sections of phelloderm and phellum cells,15to 35mm thick,separated by collapsed phellogen.Phelloderm and phellum cells are up to 100mm wide,square,rectangular,polygonal,or irregularly shaped.The cell walls are colorless.Phelloderm cells are moderately pitted with a reddish-brown content.Phellum cells have a thicker cell wall,strongly pitted,undulated contour,and a yellowish-brown to brownish-red content.Radially in between layers of phelloderm and phellum are layers of ray parenchyma cells,five to eight cells thick,rounded to radially stretched,thin walled,strongly pitted with collapsed cells and dead sieve cells.
Identification
A:
Pulverize 1g of the dried Maritime Pine.Add 10mg of the powdered material to 1mLof methanol.Add 6mLof a mixture of butanol and hydrochloric acid (95:5v/v).Heat for 2minutes in a water bath:the solution turns red.
B:Thin-Layer Chromatographic Identification Test á201ñ
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Add 2g of the powdered dried material to 20mLof water.Place in a water bath for 20minutes,and centrifuge.Extract the supernatant with 40mLof ethyl acetate.Evaporate the ethyl acetate layer to dryness under a stream of nitrogen,with gentle heating.Dissolve the residue so obtained in 0.25mLof alcohol.
Standard solution
Prepare a solution of
USP Maritime Pine Extract RSin alcohol,having a concentration of about 25mg per mL.
[NOTERetain a portion of this solution for use in
Identificationtest
C.]
Application volume:
5µL.
Developing solvent system:
a mixture of ethyl acetate,methanol,and water (100:10:6).
Spray reagent:
a mixture of alcohol and phosphoric acid (1:1),containing 1%of vanillin.
Procedure
Proceed as directed in the chapter,except to dry the plate with the aid of a current of air,spray with the
Spray reagent,and dry at 110

for 10minutes.Ared band appears in the upper part of the chromatogram of the
Test solution,at an
RFvalue of about 0.82,corresponding to a similar band in the chromatogram of the
Standard solution (presence of catechin).The lower part of the chromatogram of the
Test solutionalso shows red bands,at an
RFvalue of about 0.45
(presence of oligomeric and polymeric procyanidins).Two other red bands in the chromatogram of the
Test solutioncorrespond to those at similar
RFvalues in the chromatogram of the
Standard solution (presence of dimeric procyanidins).Ablue band appears in the chromatogram of the
Test solution between the bands for catechin and the dimeric procyanidins,corresponding in color and
RFvalue to a similar band in the chromatogram of the
Standard solution.
C:Thin-Layer Chromatographic Identification Test á201ñ
Adsorbent:
0.25-mm layer of chromatographic silica gel mixture.
Test solution
Use theTest solution prepared as directed forIdentificationtestB.
Standard solution 1
Use theStandard solution prepared as directed forIdentification testB.
Standard solution 2
Prepare a solution of ferulic acid and protocatechuic acid containing 1mg of each per mL.
Application volume:
10µL.
Developing solvent system:
a mixture of methylene chloride,methanol,glacial acetic acid,and water (80:15:2:2).
Spray reagent
Prepare a 5%ferric chloride solution in methanol.
Procedure
Proceed as directed in the chapter,except to dry the plate at 110

and examine the plate under short-wavelength UVlight.The upper third of the chromatogram of the
Test solutionexhibits three bands.The uppermost band is close to the solvent front.The middle third of the chromatogram of the
Test solutionexhibits a band corresponding in
RFvalue to the bands in the chromatograms of
Standard solution 1and
Standard solution 2(presence of ferulic acid).The lower third of the chromatogram of the
Test solutionexhibits a band corresponding to bands of similar
RFvalue in the chromatograms of
Standard solution 1and
Standard solution 2(presence of protocatechuic acid).Aband near the origin is also visible in the chromatogram of the
Test solution.Spray the plate with the
Spray reagent,and dry at 110

.The bands due to ferulic acid and protocatechuic acid turn grayish green and orange,respectively.Agrayish-green band becomes visible in the chromatogram of the
Test solution above the protocatechuic acid band
(presence of caffeic acid).The band near the origin of the chromatogram of the
Test solution turns orange.
Content of procyanidins
Reagent solution A
Prepare a mixture of butanol and hydrochloric acid (95:5).[NOTEPrepare this solution on the day of use.]
Reagent solution B
Dissolve 2g of ferric ammonium sulfate in a mixture of 100mLof water and 17.5mLof hydrochloric acid.[NOTEThis solution can be used within 15days of preparation.]
Test solution
Dry crushed Maritime Pine at 110

for 3hours.Place about 1.9g of the crushed material,accurately weighed,in a 20-mLvial,and add 10mLof methanol.Crimp the vial,and sonicate for 2minutes.Heat in boiling water for 10minutes.Cool to room temperature,allow the sediment to settle,and transfer the supernatant to a 100-mLvolumetric flask,passing it through a filter having a 0.45-µm porosity.Wash the sediment two times with 10mLof methanol,and transfer the solution into the same 100-mLvolumetric flask,again passing it through a filter having a 0.45-µm porosity.Dilute with methanol to volume,and mix.Transfer 1.0mLof that solution into a 20-mLvolumetric flask,dilute with methanol to volume,and mix.
Procedure
Transfer 1.0mLof the
Test solutionand 1.0mLof methanol to two separate 10-mLvials.To each flask add 6.0mLof
Reagent solution Aand 0.25mLof
Reagent solution Bto each flask.Seal the vials with crimp caps.Mix,and heat in a water bath for 40minutes.Quickly cool to room temperature in an ice bath.Quantitatively transfer these solutions,with the aid of
Reagent solution A,to two separate 10-mLvolumetric flasks,dilute with
Reagent solution Ato volume,and mix.Determine the absorbance of the solution obtained from the
Test solutionat 546nm,using the methanol-containing solution as the blank.Calculate the percentage of total procyanidins in the portion of Maritime Pine taken by the formula:
(2000AU)/(36.7W),
in which
AUis the absorbance of the solution obtained from the
Test solution;36.7is the absorptivity of the maritime pine procyanidins;and
Wis the weight,in g,of the Maritime Pine taken to prepare the
Test solution.