Sodium Acetate Solution
»Sodium Acetate Solution is an aqueous solution of Sodium Acetate.It contains not less than 97.0percent and not more than 103.0percent (w/w)of the labeled amount of C2H3NaO2.
Packaging and storage— Preserve in tight containers.
Identification— It responds to the tests for Sodium á191ñand for Acetate á191ñ.
pHá791ñ: between 7.5and 9.2,when diluted with carbon dioxide-free water to contain 5%of solids.
Insoluble matter— Dilute a quantity of Solution,equivalent to 20g of anhydrous sodium acetate,with water to 150mL,heat to boiling,and digest in a covered beaker on a steam bath for 1hour.Filter through a tared filtering crucible,wash thoroughly,and dry at 105:the weight of the residue does not exceed 1mg (0.005%).
Chloride á221ñ Aquantity of Solution,equivalent to 1.0g of anhydrous sodium acetate,shows no more chloride than corresponds to 0.50mLof 0.020Nhydrochloric acid (0.035%).
Sulfate á221ñ Aquantity of Solution,equivalent to 10g of anhydrous sodium acetate,shows no more sulfate than corresponds to 0.50mLof 0.020Nsulfuric acid (0.005%).
Calcium and magnesium— Dilute a quantity of Solution,equivalent to 1.0g of anhydrous sodium acetate,to 100mLwith water.To 20mLof this solution add 2mLeach of 6Nammonium hydroxide,ammonium oxalate TS,and sodium phosphate TS:no turbidity is produced within 5minutes.
Potassium— To a quantity of Solution,equivalent to 3.0g of anhydrous sodium acetate,add 0.2mLof sodium bitartrate TS:no turbidity is produced within 5minutes.
Heavy metals,Method Iá231ñ Dilute a quantity of Solution,equivalent to 2.0g of anhydrous sodium acetate,with water to 25mL,and use glacial acetic acid instead of 1Nacetic acid for adjustment of the pH:the limit is 0.001%.
Assay— Weigh accurately about 1g of Solution into a 250-mLconical flask,cautiously add (in a fume hood)2.6mLof acetic anhydride,mix,and allow to stand for 5minutes.Add 25mLof glacial acetic acid and 2drops of p-naphtholbenzein TS,and titrate with 0.1Nperchloric acid VS.Perform a blank determination,using 0.5mLof water,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 8.203mg of C2H3NaO2.
Auxiliary Information— Staff Liaison:Karen A Russo,Ph.D.,Scientist
Expert Committee:(PA1)Pharmaceutical Analysis 1
USP28–NF23Page 1775
Phone Number:1-301-816-8379