10H-Phenothiazine,10-[3-(4-methyl-1-piperazinyl)propyl-[2-(trifluoromethyl)-,dihydrochloride.
10-[3-(4-Methyl-1-piperazinyl)propyl-[2-(trifluoromethyl)phenothiazine dihydrochloride
[440-17-5].
Change to read:
Packaging and storage
Preserve in tight,light-resistant containers.

Store at 25

,excursions permitted between 15

and 30

.
USP28
Identification
A:
Infrared Absorption á197Mñ.
B:
Ultraviolet Absorption á197Uñ
Solution:
10µg per mL.
Medium:
0.1Nhydrochloric acid.
Absorptivities at 255nm,calculated on the dried basis,do not differ by more than 2.0%.
C:
Asolution (1in 100)responds to the tests for Chloride á191ñ.
D:
Prepare a solution in methanol containing 1.2mg per mL.Apply 5µLeach of this solution and a solution of
USP Trifluoperazine Hydrochloride RSin methanol containing 1.2mg per mLto a suitable thin-layer chromatographic plate (see
Chromatography á621ñ)coated with a 0.25-mm layer of chromatographic silica gel.Allow the spots to dry,and develop the chromatogram in a solvent system consisting of a mixture of acetone and ammonium hydroxide (200:1)until the solvent front has moved about three-fourths of the length of the plate.Remove the plate from the developing chamber,mark the solvent front,and allow the solvent to evaporate.Locate the spots on the plate by lightly spraying with a solution of iodoplatinic acid prepared by dissolving 100mg of chloroplatinic acid in 1mLof 1Nhydrochloric acid,adding 25mLof potassium iodide solution (1in 25),diluting with water to 100mL,and then adding 0.5mLof formic acid:the
RFvalue of the principal spot from the test solution corresponds to that from the Standard solution.
pHá791ñ:
between 1.7and 2.6,in a solution (1in 20).
Organic volatile impurities,Method Iá467ñ:
meets the requirements.
Assay
Dissolve about 500mg of Trifluoperazine Hydrochloride,previously dried and accurately weighed,in 50mLof glacial acetic acid,and add crystal violet TSand 15mLof mercuric acetate TS.Titrate with 0.1Nperchloric acid VSto a blue-green endpoint.Perform a blank determination,and make any necessary correction.Each mLof 0.1Nperchloric acid is equivalent to 24.02mg of C21H24F3N3S·2HCl.