Packaging and storage
Preserve in well-closed containers.
Labeling
The label states the content of anhydrous aluminum dichlorohydrate.
Identification
Asolution (1in 10)responds to the tests for Aluminum á191ñand for Chloride á191ñ.
pHá791ñ:
between 3.0and 5.0,in a solution [15in 100(w/w)].
Limit of iron
Using Aluminum Dichlorohydrate instead of Aluminum Chlorohydrate,proceed as directed in the test for
Limit of ironunder
Aluminum Chlorohydrate.The limit is 150µg per g.
Aluminum/chloride atomic ratio
Divide the percentage of aluminum found in the test for
Content of aluminumby the percentage of chloride found in the test for
Content of chlorideand multiply by 35.453/26.98,in which 35.453and 26.98are the atomic weights of chlorine and aluminum,respectively:the ratio is between 0.90:1and 1.25:1.
Assay
Calculate the percentage of anhydrous aluminum dichlorohydrate in the Aluminum Dichlorohydrate by the formula:
Al({26.98x +[17.01(3x -1)]+35.453}/26.98x),
in which
Alis the percentage of aluminum found in the test for
Content of aluminum,
xis the aluminum/chloride atomic ratio,26.98is the atomic weight of aluminum,17.01is the molecular weight of the hydroxide anion (OH),and 35.453is the atomic weight of chlorine (Cl).