Packaging and storage
Preserve in well-closed containers.
Labeling
Label Solution to state the solvent used and the claimed concentration of anhydrous aluminum dichlorohydrate contained therein.
Identification
A:
Asolution containing the equivalent of about 100mg of anhydrous aluminum dichlorohydrate per mLresponds to the tests for Aluminum á191ñand for Chloride á191ñ.
B:
Infrared Absorption á197Fñ(where propylene glycol is indicated on the label)
Test specimen
Add about 10mLof isopropyl alcohol to 2g of Solution,mix,and filter.Evaporate the filtrate to about 1mLon a steam bath.Deposit this solution on a silver chloride disk.
Standard specimen:
a similar preparation of propylene glycol.
C:
Infrared Absorption á197Fñ(where dipropylene glycol is indicated on the label)
Test specimen
Add about 10mLof isopropyl alcohol to 2g of Solution,mix,and filter.Evaporate the filtrate to about 1mLon a steam bath.Deposit this solution on a silver chloride disk.
Standard specimen:
a similar preparation of dipropylene glycol.
D:
Identification of alcohol(where stated on the label)Mix 5drops of Solution in a small beaker with 1mLof potassium permanganate solution (1in 100)and 5drops of 2Nsulfuric acid,and cover the beaker immediately with filter paper moistened with a freshly prepared solution of 0.1g of sodium nitroferricyanide and 0.25g of piperazine in 5mLof water:an intense blue color is produced on the filter paper,the color becoming paler after a few minutes.
pHá791ñ:
between 3.0and 5.0,in a solution prepared by diluting 3g of the Solution with water to obtain 10mL.
Arsenic,Method Iá211ñ
Prepare the
Test Preparationusing an accurately weighed quantity of the Solution.The limit is 2µg per g.
Heavy metals,Method Iá231ñ
Prepare the
Test Preparationusing an accurately weighed quantity of the Solution.The limit is 10µg per g.
Aluminum/chloride atomic ratio
Divide the percentage of aluminum found in the test for
Content of aluminumby the percentage of chloride found in the test for
Content of chloride,and multiply by 35.453/26.98,in which 35.453and 26.98are the atomic weights of chlorine and aluminum respectively:the ratio is between 0.90:1and 1.25:1.
Assay
Calculate the percentage of anhydrous aluminum dichlorohydrate in the Solution by the formula:
Al({26.98x +[17.01(3x -1)]+35.453}/26.98x),
in which
Alis the percentage of aluminum found in the test for
Content of aluminum,
xis the aluminum/chloride atomic ratio found in the test for
aluminum/chloride atomic ratio,26.98is the atomic weight of aluminum,17.01is the molecular weight of the hydroxide anion (OH),and 35.453is the atomic weight of chlorine (Cl).