Aly(OH)3y-zClz·nH2O·mC3H8O2
Aluminum chlorohydroxide propylene glycol complex.
Aluminum hydroxychloride propylene glycol complex.
Packaging and storage—
Preserve in well-closed containers.
Labeling—
The label states the content of anhydrous aluminum sesquichlorohydrate.
Identification—
A:
Asolution (1in 10)responds to the tests for Aluminum á191ñand for Chloride á191ñ.
B:
Infrared Absorption á197Fñ—
Test specimen—
Dissolve 0.5g in about 40mLof water,and while mixing adjust with 2.5Nsodium hydroxide to a pHof 9.55±0.05.Filter the suspension of precipitate thus obtained.Evaporate about 15mLof the filtrate to about 1mLon a hot plate.Deposit this solution on a silver chloride disk.
Standard specimen:
a similar preparation of propylene glycol.
pHá791ñ:
between 3.0and 5.0,in a solution [15in 100(w/w)].
Limit of iron—
Using Aluminum Sesquichlorohydrex Propylene Glycol instead of Aluminum Chlorohydrate,proceed as directed in the test for
Limit of ironunder
Aluminum Chlorohydrate.The limit is 150µg per g.
Aluminum/chloride atomic ratio—
Divide the percentage of aluminum found in the test for
Content of aluminumby the percentage of chloride found in the test for
Content of chloride,and multiply by 35.453/26.98,in which 35.453and 26.98are the atomic weights of chlorine and aluminum,respectively:the ratio is between 1.26:1and 1.90:1.
Assay—
Calculate the percentage of anhydrous aluminum sesquichlorohydrate in the Aluminum Sesquichlorohydrex Propylene Glycol by the formula:
Al({26.98x +[17.01(3x -1)]+35.453}/26.98x),
in which
Alis the percentage of aluminum found in the test for
Content of aluminum,
xis the aluminum/chloride atomic ratio found in the test for
Aluminum/chloride atomic ratio,26.98is the atomic weight of aluminum,17.01is the molecular weight of the hydroxide anion (OH),and 35.453is the atomic weight of chlorine (Cl).