1,2,3-Propanetricarboxylic acid,hydroxy-,magnesium salt (2:3).
Magnesium citrate (3:2)
[3344-18-1].
Packaging and storage
Preserve in tight containers.
Labeling
Magnesium Citrate that loses not more than 2.0%of its weight in the test for
Loss on dryingmay be labeled as Anhydrous Magnesium Citrate.
Identification
A:
Asolution (10mg per mL)responds to the tests for Magnesium á191ñ.
B:
Asolution (80mg per mL)responds to the tests for Citrate á191ñ.
pHá791ñ:
between 5.0and 9.0,in a suspension (50mg per mL).
Loss on drying á731ñ
Dry 1g in a mechanical convection oven at 135

for 16hours,then to constant weight:it loses not more than 29%of its weight,except that where it is labeled as anhydrous,it loses not more than 2.0%of its weight.
Chloride á221ñ
A300-mg portion shows no more chloride than corresponds to 0.20mLof 0.020Nhydrochloric acid (0.05%).
Sulfate á221ñ
A100-mg portion shows no more sulfate than corresponds to 0.20mLof 0.020Nsulfuric acid (0.2%).
Heavy metals,Method Iá231ñ
Dissolve 0.4g in 25mLof water,and proceed as directed for
Test Preparation,except to use glacial acetic acid to adjust the pH:the limit is 50µg per g.
Iron á241ñ
Boil 50mg with 5mLof 2Nnitric acid for 1minute.Cool,dilute with water to 45mL,add 2mLof hydrochloric acid,and mix:the limit is 200µg per g.
Limit of calcium
Dilute hydrochloric acid
,
Lanthanum solution,
Standard preparations,and
Blank solutionPrepare as directed in the test for
Calciumunder
Magnesium Carbonate.
Test preparation
Transfer 250mg of Magnesium Citrate to a beaker,add 30mLof Dilute hydrochloric acid,and stir until dissolved.Transfer the solution so obtained to a 200-mLvolumetric flask containing 4mLof Lanthanum solution,dilute with water to volume,and mix.
Organic volatile impurities,Method IVá467ñ:
meets the requirements.
Assay
Weigh accurately about 400mg of Magnesium Citrate,dissolve in 50mLof water,add 20mLof ammoniaammonium chloride buffer TSand 0.1mLof eriochrome black TS,and titrate with 0.05Medetate disodium VSto a blue endpoint.Perform a blank determination,and make any necessary correction.From the volume of 0.05Medetate disodium consumed,deduct the volume of 0.05Medetate disodium corresponding to the amount of calcium in the portion of Magnesium Citrate taken,based on the amount of calcium found in the test for Limit of calcium.Each mg of calcium (Ca)is equivalent to 0.25mLof 0.05Medetate disodium.The difference is the volume of 0.05Medetate disodium consumed by the magnesium.Each mLof 0.05Medetate disodium is equivalent to 1.215mg of magnesium (Mg).